TUGAS
Angkan 0desimal=0biner
a.
43=
43:2=21 sisa 1 43=101011
21:2=10 sisa 1
10:2=5 sisa 0
5:2=2 sisa 1
2:2=1 sisa 0
1:2=0 sisa 1
b.
0,375
1024
|
512
|
256
|
128
|
64
|
32
|
16
|
8
|
4
|
2
|
1
|
 |
 |
1
|
0
|
1
|
1
|
1
|
0
|
1
|
1
|
1
|
Dari perhitungan
di atas di dapatkan bahwa 0,378desimal=0,101110111biner
c.
64= 64:2=32
sisa 0
32:2=16 sisa 0
16:2=8 sisa 0
8:2=4 sisa 0
4:2=2 sisa 0
2:2=1 sisa 0
1:2=0 sisa 1 Maka 64desimal=1000000biner
d.
0,4378
8192
|
4096
|
2048
|
1024
|
512
|
256
|
128
|
64
|
32
|
16
|
8
|
4
|
2
|
1
|
 |
1
|
1
|
0
|
0
|
0
|
1
|
1
|
1
|
0
|
1
|
0
|
1
|
0
|
Dari perhitungan
di atas di dapatkan bahwa 0,4378desimal=0,1100011101010biner
e. 6,25
32
|
16
|
8
|
4
|
2
|
1
|
|
|
|
|
1
|
1
|
0
|
6 |
1
|
1
|
0
|
0
|
1
|
25 |
Dari perhitungan
di atas di dapatkan bahwa 6,25desimal=110,11001biner
2. Konversi biner ke desimal
Angkan 0biner=0desimal
a.
0,001101
001101 =1x23+1x22+0x21+1x20
=8+4+1
=13 0,001101biner=0,13desimal
b.
0,1011
0,1011 = 1x23+0x22+1x21+1x20
=8+3=11 0,1011=0,11
3. Penjumlahan
a.
1001,1+1011,01
1001,1 = 1x23+0x22+0x21+1x20
, 1x20
=
8+1 , 1
= 9,1
1011,01
= 1x23+0x22+1x21+1x20 , 0x21+1x20
=8+2+1
, 1
=
11,1
1001,1+1011,01=9,1+11,1=20,2desimal=10100,10biner
b.
1011,01+1001,11
1011,01 = 1x23+0x22+1x21+1x20
, 0x21+1x20
=8+2+1
, 1
= 11,1
1001,11 = 1x23+0x22+0x21+1x20
, 1x21+1x20
= 8+1 , 2+1
= 9,3
1011,01+1001,11= 11,1+9,3=20,4desimal=10100,
c.
11111,1+10010,1
11111,1 = 1x24+1x23+1x22+1x21+1x20
, 1x20
= 16+8+4+2+1 , 1
=31,1
10010,1 = 1x24+0x23+0x22+1x21+0x20
, 1x20
=16+2
, 1
= 18,1
11111,1+10010,1=31,1+18,1=49,2desimal=110001biner
d.
10,11+10,01
10,11 = 1x21+0x20
, 1x21+1x20
=2,3
10,01 = 1x21+0x20
, 0x21+1x20
=2,1
10,11+10,01=2,3+2,1=
4,4desimal=100,100biner
e.
101,1 + 111,11
101,1 = 1x22+0x21+1x20
,
1x20
=4+1
, 1
=
5,1
111,1 = 1x22+1x21+1x20
,
1x21+1x20
=4+2+1
, 2+1
=7,3
101,1 + 111,11=5,1+7,3=12,4desimal=1100,100
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